diff --git a/backend/src/main/java/com/designhub/service/TaskItemService.java b/backend/src/main/java/com/designhub/service/TaskItemService.java
index 2b28872..0412378 100644
--- a/backend/src/main/java/com/designhub/service/TaskItemService.java
+++ b/backend/src/main/java/com/designhub/service/TaskItemService.java
@@ -134,17 +134,26 @@ public class TaskItemService {
         if (result.getRecords() != null && !result.getRecords().isEmpty()) {
             fillUnlockStatusForItems(result.getRecords(), filterDeptId);
             
-            // 🔥 按排序方式和解锁状态排序
+            // 🔥 按排序方式和解锁状态排序：可抢单的排前面
             List<TaskItem> sortedRecords = new java.util.ArrayList<>(result.getRecords());
             sortedRecords.sort((a, b) -> {
-                // 首先按解锁状态排序：已解锁的排前面
-                boolean aUnlocked = "unlocked".equals(a.getUnlockStatus()) || a.getUnlockStatus() == null;
-                boolean bUnlocked = "unlocked".equals(b.getUnlockStatus()) || b.getUnlockStatus() == null;
-                if (aUnlocked != bUnlocked) {
-                    return aUnlocked ? -1 : 1;
+                // 1. 首先按解锁状态排序：可抢单(unlocked/null)的排前面，排队中(queuing)的排后面
+                boolean aCanGrab = a.getCanGrab() != null && a.getCanGrab();
+                boolean bCanGrab = b.getCanGrab() != null && b.getCanGrab();
+                if (aCanGrab != bCanGrab) {
+                    return aCanGrab ? -1 : 1;
                 }
                 
-                // 然后按时间排序
+                // 2. 如果都是排队中，按队列位置排序（位置小的排前面）
+                if (!aCanGrab && !bCanGrab) {
+                    Integer posA = a.getQueuePosition();
+                    Integer posB = b.getQueuePosition();
+                    if (posA != null && posB != null && !posA.equals(posB)) {
+                        return posA.compareTo(posB);
+                    }
+                }
+                
+                // 3. 最后按时间排序
                 LocalDateTime timeA = a.getCreateTime();
                 LocalDateTime timeB = b.getCreateTime();
                 if (timeA == null && timeB == null) return 0;